Narrowing

Imagine we have a function called padLeft.

ts
function padLeft(padding: number | string, input: string): string {
  throw new Error("Not implemented yet!");
}
Try

If padding is a number, it will treat that as the number of spaces we want to prepend to input. If padding is a string, it should just prepend padding to input. Let’s try to implement the logic for when padLeft is passed a number for padding.

ts
function padLeft(padding: number | string, input: string) {
  return " ".repeat(padding) + input;
Argument of type 'string | number' is not assignable to parameter of type 'number'.
  Type 'string' is not assignable to type 'number'.2345Argument of type 'string | number' is not assignable to parameter of type 'number'.
  Type 'string' is not assignable to type 'number'.
}
Try

Uh-oh, we’re getting an error on padding. TypeScript is warning us that adding a number | string to a number might not give us what we want, and it’s right. In other words, we haven’t explicitly checked if padding is a number first, nor are we handling the case where it’s a string, so let’s do exactly that.

ts
function padLeft(padding: number | string, input: string) {
  if (typeof padding === "number") {
    return " ".repeat(padding) + input;
  }
  return padding + input;
}
Try

If this mostly looks like uninteresting JavaScript code, that’s sort of the point. Apart from the annotations we put in place, this TypeScript code looks like JavaScript. The idea is that TypeScript’s type system aims to make it as easy as possible to write typical JavaScript code without bending over backwards to get type safety.

While it might not look like much, there’s actually a lot going under the covers here. Much like how TypeScript analyzes runtime values using static types, it overlays type analysis on JavaScript’s runtime control flow constructs like if/else, conditional ternaries, loops, truthiness checks, etc., which can all affect those types.

Within our if check, TypeScript sees typeof padding === "number" and understands that as a special form of code called a type guard. TypeScript follows possible paths of execution that our programs can take to analyze the most specific possible type of a value at a given position. It looks at these special checks (called type guards) and assignments, and the process of refining types to more specific types than declared is called narrowing. In many editors we can observe these types as they change, and we’ll even do so in our examples.

ts
function padLeft(padding: number | string, input: string) {
  if (typeof padding === "number") {
    return " ".repeat(padding) + input;
                        
(parameter) padding: number
  }
  return padding + input;
           
(parameter) padding: string
}
Try

There are a couple of different constructs TypeScript understands for narrowing.

typeof type guards

As we’ve seen, JavaScript supports a typeof operator which can give very basic information about the type of values we have at runtime. TypeScript expects this to return a certain set of strings:

  • "string"
  • "number"
  • "bigint"
  • "boolean"
  • "symbol"
  • "undefined"
  • "object"
  • "function"

Like we saw with padLeft, this operator comes up pretty often in a number of JavaScript libraries, and TypeScript can understand it to narrow types in different branches.

In TypeScript, checking against the value returned by typeof is a type guard. Because TypeScript encodes how typeof operates on different values, it knows about some of its quirks in JavaScript. For example, notice that in the list above, typeof doesn’t return the string null. Check out the following example:

ts
function printAll(strs: string | string[] | null) {
  if (typeof strs === "object") {
    for (const s of strs) {
Object is possibly 'null'.2531Object is possibly 'null'.
      console.log(s);
    }
  } else if (typeof strs === "string") {
    console.log(strs);
  } else {
    // do nothing
  }
}
Try

In the printAll function, we try to check if strs is an object to see if it’s an array type (now might be a good time to reinforce that arrays are object types in JavaScript). But it turns out that in JavaScript, typeof null is actually "object"! This is one of those unfortunate accidents of history.

Users with enough experience might not be surprised, but not everyone has run into this in JavaScript; luckily, TypeScript lets us know that strs was only narrowed down to string[] | null instead of just string[].

This might be a good segue into what we’ll call “truthiness” checking.

Truthiness narrowing

Truthiness might not be a word you’ll find in the dictionary, but it’s very much something you’ll hear about in JavaScript.

In JavaScript, we can use any expression in conditionals, &&s, ||s, if statements, Boolean negations (!), and more. As an example, if statements don’t expect their condition to always have the type boolean.

ts
function getUsersOnlineMessage(numUsersOnline: number) {
  if (numUsersOnline) {
    return `There are ${numUsersOnline} online now!`;
  }
  return "Nobody's here. :(";
}
Try

In JavaScript, constructs like if first “coerce” their conditions to booleans to make sense of them, and then choose their branches depending on whether the result is true or false. Values like

  • 0
  • NaN
  • "" (the empty string)
  • 0n (the bigint version of zero)
  • null
  • undefined

all coerce to false, and other values get coerced true. You can always coerce values to booleans by running them through the Boolean function, or by using the shorter double-Boolean negation. (The latter has the advantage that TypeScript infers a narrow literal boolean type true, while inferring the first as type boolean.)

ts
// both of these result in 'true'
Boolean("hello"); // type: boolean, value: true
!!"world"; // type: true,    value: true
Try

It’s fairly popular to leverage this behavior, especially for guarding against values like null or undefined. As an example, let’s try using it for our printAll function.

ts
function printAll(strs: string | string[] | null) {
  if (strs && typeof strs === "object") {
    for (const s of strs) {
      console.log(s);
    }
  } else if (typeof strs === "string") {
    console.log(strs);
  }
}
Try

You’ll notice that we’ve gotten rid of the error above by checking if strs is truthy. This at least prevents us from dreaded errors when we run our code like:

txt
TypeError: null is not iterable

Keep in mind though that truthiness checking on primitives can often be error prone. As an example, consider a different attempt at writing printAll

ts
function printAll(strs: string | string[] | null) {
  // !!!!!!!!!!!!!!!!
  //  DON'T DO THIS!
  //   KEEP READING
  // !!!!!!!!!!!!!!!!
  if (strs) {
    if (typeof strs === "object") {
      for (const s of strs) {
        console.log(s);
      }
    } else if (typeof strs === "string") {
      console.log(strs);
    }
  }
}
Try

We wrapped the entire body of the function in a truthy check, but this has a subtle downside: we may no longer be handling the empty string case correctly.

TypeScript doesn’t hurt us here at all, but this is behavior worth noting if you’re less familiar with JavaScript. TypeScript can often help you catch bugs early on, but if you choose to do nothing with a value, there’s only so much that it can do without being overly prescriptive. If you want, you can make sure you handle situations like these with a linter.

One last word on narrowing by truthiness is that Boolean negations with ! filter out from negated branches.

ts
function multiplyAll(
  values: number[] | undefined,
  factor: number
): number[] | undefined {
  if (!values) {
    return values;
  } else {
    return values.map((x) => x * factor);
  }
}
Try

Equality narrowing

TypeScript also uses switch statements and equality checks like ===, !==, ==, and != to narrow types. For example:

ts
function example(x: string | number, y: string | boolean) {
  if (x === y) {
    // We can now call any 'string' method on 'x' or 'y'.
    x.toUpperCase();
          
(method) String.toUpperCase(): string
    y.toLowerCase();
          
(method) String.toLowerCase(): string
  } else {
    console.log(x);
               
(parameter) x: string | number
    console.log(y);
               
(parameter) y: string | boolean
  }
}
Try

When we checked that x and y are both equal in the above example, TypeScript knew their types also had to be equal. Since string is the only common type that both x and y could take on, TypeScript knows that x and y must be a string in the first branch.

Checking against specific literal values (as opposed to variables) works also. In our section about truthiness narrowing, we wrote a printAll function which was error-prone because it accidentally didn’t handle empty strings properly. Instead we could have done a specific check to block out nulls, and TypeScript still correctly removes null from the type of strs.

ts
function printAll(strs: string | string[] | null) {
  if (strs !== null) {
    if (typeof strs === "object") {
      for (const s of strs) {
                       
(parameter) strs: string[]
        console.log(s);
      }
    } else if (typeof strs === "string") {
      console.log(strs);
                   
(parameter) strs: string
    }
  }
}
Try

JavaScript’s looser equality checks with == and != also get narrowed correctly. If you’re unfamiliar, checking whether something == null actually not only checks whether it is specifically the value null - it also checks whether it’s potentially undefined. The same applies to == undefined: it checks whether a value is either null or undefined.

ts
interface Container {
  value: number | null | undefined;
}
 
function multiplyValue(container: Container, factor: number) {
  // Remove both 'null' and 'undefined' from the type.
  if (container.value != null) {
    console.log(container.value);
                           
(property) Container.value: number
 
    // Now we can safely multiply 'container.value'.
    container.value *= factor;
  }
}
Try

The in operator narrowing

JavaScript has an operator for determining if an object has a property with a name: the in operator. TypeScript takes this into account as a way to narrow down potential types.

For example, with the code: "value" in x. where "value" is a string literal and x is a union type. The “true” branch narrows x’s types which have either an optional or required property value, and the “false” branch narrows to types which have an optional or missing property value.

ts
type Fish = { swim: () => void };
type Bird = { fly: () => void };
 
function move(animal: Fish | Bird) {
  if ("swim" in animal) {
    return animal.swim();
  }
 
  return animal.fly();
}
Try

To reiterate optional properties will exist in both sides for narrowing, for example a human could both swim and fly (with the right equipment) and thus should show up in both sides of the in check:

ts
type Fish = { swim: () => void };
type Bird = { fly: () => void };
type Human = { swim?: () => void; fly?: () => void };
 
function move(animal: Fish | Bird | Human) {
  if ("swim" in animal) {
    animal;
      
(parameter) animal: Fish | Human
  } else {
    animal;
      
(parameter) animal: Bird | Human
  }
}
Try

instanceof narrowing

JavaScript has an operator for checking whether or not a value is an “instance” of another value. More specifically, in JavaScript x instanceof Foo checks whether the prototype chain of x contains Foo.prototype. While we won’t dive deep here, and you’ll see more of this when we get into classes, they can still be useful for most values that can be constructed with new. As you might have guessed, instanceof is also a type guard, and TypeScript narrows in branches guarded by instanceofs.

ts
function logValue(x: Date | string) {
  if (x instanceof Date) {
    console.log(x.toUTCString());
               
(parameter) x: Date
  } else {
    console.log(x.toUpperCase());
               
(parameter) x: string
  }
}
Try

Assignments

As we mentioned earlier, when we assign to any variable, TypeScript looks at the right side of the assignment and narrows the left side appropriately.

ts
let x = Math.random() < 0.5 ? 10 : "hello world!";
   
let x: string | number
x = 1;
 
console.log(x);
           
let x: number
x = "goodbye!";
 
console.log(x);
           
let x: string
Try

Notice that each of these assignments is valid. Even though the observed type of x changed to number after our first assignment, we were still able to assign a string to x. This is because the declared type of x - the type that x started with - is string | number, and assignability is always checked against the declared type.

If we’d assigned a boolean to x, we’d have seen an error since that wasn’t part of the declared type.

ts
let x = Math.random() < 0.5 ? 10 : "hello world!";
   
let x: string | number
x = 1;
 
console.log(x);
           
let x: number
x = true;
Type 'boolean' is not assignable to type 'string | number'.2322Type 'boolean' is not assignable to type 'string | number'.
 
console.log(x);
           
let x: string | number
Try

Control flow analysis

Up until this point, we’ve gone through some basic examples of how TypeScript narrows within specific branches. But there’s a bit more going on than just walking up from every variable and looking for type guards in ifs, whiles, conditionals, etc. For example

ts
function padLeft(padding: number | string, input: string) {
  if (typeof padding === "number") {
    return " ".repeat(padding) + input;
  }
  return padding + input;
}
Try

padLeft returns from within its first if block. TypeScript was able to analyze this code and see that the rest of the body (return padding + input;) is unreachable in the case where padding is a number. As a result, it was able to remove number from the type of padding (narrowing from string | number to string) for the rest of the function.

This analysis of code based on reachability is called control flow analysis, and TypeScript uses this flow analysis to narrow types as it encounters type guards and assignments. When a variable is analyzed, control flow can split off and re-merge over and over again, and that variable can be observed to have a different type at each point.

ts
function example() {
  let x: string | number | boolean;
 
  x = Math.random() < 0.5;
 
  console.log(x);
             
let x: boolean
 
  if (Math.random() < 0.5) {
    x = "hello";
    console.log(x);
               
let x: string
  } else {
    x = 100;
    console.log(x);
               
let x: number
  }
 
  return x;
        
let x: string | number
}
Try

Using type predicates

We’ve worked with existing JavaScript constructs to handle narrowing so far, however sometimes you want more direct control over how types change throughout your code.

To define a user-defined type guard, we simply need to define a function whose return type is a type predicate:

ts
function isFish(pet: Fish | Bird): pet is Fish {
  return (pet as Fish).swim !== undefined;
}
Try

pet is Fish is our type predicate in this example. A predicate takes the form parameterName is Type, where parameterName must be the name of a parameter from the current function signature.

Any time isFish is called with some variable, TypeScript will narrow that variable to that specific type if the original type is compatible.

ts
// Both calls to 'swim' and 'fly' are now okay.
let pet = getSmallPet();
 
if (isFish(pet)) {
  pet.swim();
} else {
  pet.fly();
}
Try

Notice that TypeScript not only knows that pet is a Fish in the if branch; it also knows that in the else branch, you don’t have a Fish, so you must have a Bird.

You may use the type guard isFish to filter an array of Fish | Bird and obtain an array of Fish:

ts
const zoo: (Fish | Bird)[] = [getSmallPet(), getSmallPet(), getSmallPet()];
const underWater1: Fish[] = zoo.filter(isFish);
// or, equivalently
const underWater2: Fish[] = zoo.filter(isFish) as Fish[];
 
// The predicate may need repeating for more complex examples
const underWater3: Fish[] = zoo.filter((pet): pet is Fish => {
  if (pet.name === "sharkey") return false;
  return isFish(pet);
});
Try

In addition, classes can use this is Type to narrow their type.

Discriminated unions

Most of the examples we’ve looked at so far have focused around narrowing single variables with simple types like string, boolean, and number. While this is common, most of the time in JavaScript we’ll be dealing with slightly more complex structures.

For some motivation, let’s imagine we’re trying to encode shapes like circles and squares. Circles keep track of their radiuses and squares keep track of their side lengths. We’ll use a field called kind to tell which shape we’re dealing with. Here’s a first attempt at defining Shape.

ts
interface Shape {
  kind: "circle" | "square";
  radius?: number;
  sideLength?: number;
}
Try

Notice we’re using a union of string literal types: "circle" and "square" to tell us whether we should treat the shape as a circle or square respectively. By using "circle" | "square" instead of string, we can avoid misspelling issues.

ts
function handleShape(shape: Shape) {
  // oops!
  if (shape.kind === "rect") {
This condition will always return 'false' since the types '"circle" | "square"' and '"rect"' have no overlap.2367This condition will always return 'false' since the types '"circle" | "square"' and '"rect"' have no overlap.
    // ...
  }
}
Try

We can write a getArea function that applies the right logic based on if it’s dealing with a circle or square. We’ll first try dealing with circles.

ts
function getArea(shape: Shape) {
  return Math.PI * shape.radius ** 2;
Object is possibly 'undefined'.2532Object is possibly 'undefined'.
}
Try

Under strictNullChecks that gives us an error - which is appropriate since radius might not be defined. But what if we perform the appropriate checks on the kind property?

ts
function getArea(shape: Shape) {
  if (shape.kind === "circle") {
    return Math.PI * shape.radius ** 2;
Object is possibly 'undefined'.2532Object is possibly 'undefined'.
  }
}
Try

Hmm, TypeScript still doesn’t know what to do here. We’ve hit a point where we know more about our values than the type checker does. We could try to use a non-null assertion (a ! after shape.radius) to say that radius is definitely present.

ts
function getArea(shape: Shape) {
  if (shape.kind === "circle") {
    return Math.PI * shape.radius! ** 2;
  }
}
Try

But this doesn’t feel ideal. We had to shout a bit at the type-checker with those non-null assertions (!) to convince it that shape.radius was defined, but those assertions are error-prone if we start to move code around. Additionally, outside of strictNullChecks we’re able to accidentally access any of those fields anyway (since optional properties are just assumed to always be present when reading them). We can definitely do better.

The problem with this encoding of Shape is that the type-checker doesn’t have any way to know whether or not radius or sideLength are present based on the kind property. We need to communicate what we know to the type checker. With that in mind, let’s take another swing at defining Shape.

ts
interface Circle {
  kind: "circle";
  radius: number;
}
 
interface Square {
  kind: "square";
  sideLength: number;
}
 
type Shape = Circle | Square;
Try

Here, we’ve properly separated Shape out into two types with different values for the kind property, but radius and sideLength are declared as required properties in their respective types.

Let’s see what happens here when we try to access the radius of a Shape.

ts
function getArea(shape: Shape) {
  return Math.PI * shape.radius ** 2;
Property 'radius' does not exist on type 'Shape'.
  Property 'radius' does not exist on type 'Square'.2339Property 'radius' does not exist on type 'Shape'.
  Property 'radius' does not exist on type 'Square'.
}
Try

Like with our first definition of Shape, this is still an error. When radius was optional, we got an error (with strictNullChecks enabled) because TypeScript couldn’t tell whether the property was present. Now that Shape is a union, TypeScript is telling us that shape might be a Square, and Squares don’t have radius defined on them! Both interpretations are correct, but only the union encoding of Shape will cause an error regardless of how strictNullChecks is configured.

But what if we tried checking the kind property again?

ts
function getArea(shape: Shape) {
  if (shape.kind === "circle") {
    return Math.PI * shape.radius ** 2;
                      
(parameter) shape: Circle
  }
}
Try

That got rid of the error! When every type in a union contains a common property with literal types, TypeScript considers that to be a discriminated union, and can narrow out the members of the union.

In this case, kind was that common property (which is what’s considered a discriminant property of Shape). Checking whether the kind property was "circle" got rid of every type in Shape that didn’t have a kind property with the type "circle". That narrowed shape down to the type Circle.

The same checking works with switch statements as well. Now we can try to write our complete getArea without any pesky ! non-null assertions.

ts
function getArea(shape: Shape) {
  switch (shape.kind) {
    case "circle":
      return Math.PI * shape.radius ** 2;
                        
(parameter) shape: Circle
    case "square":
      return shape.sideLength ** 2;
              
(parameter) shape: Square
  }
}
Try

The important thing here was the encoding of Shape. Communicating the right information to TypeScript - that Circle and Square were really two separate types with specific kind fields - was crucial. Doing that let us write type-safe TypeScript code that looks no different than the JavaScript we would’ve written otherwise. From there, the type system was able to do the “right” thing and figure out the types in each branch of our switch statement.

As an aside, try playing around with the above example and remove some of the return keywords. You’ll see that type-checking can help avoid bugs when accidentally falling through different clauses in a switch statement.

Discriminated unions are useful for more than just talking about circles and squares. They’re good for representing any sort of messaging scheme in JavaScript, like when sending messages over the network (client/server communication), or encoding mutations in a state management framework.

The never type

When narrowing, you can reduce the options of a union to a point where you have removed all possibilities and have nothing left. In those cases, TypeScript will use a never type to represent a state which shouldn’t exist.

Exhaustiveness checking

The never type is assignable to every type; however, no type is assignable to never (except never itself). This means you can use narrowing and rely on never turning up to do exhaustive checking in a switch statement.

For example, adding a default to our getArea function which tries to assign the shape to never will raise when every possible case has not been handled.

ts
type Shape = Circle | Square;
 
function getArea(shape: Shape) {
  switch (shape.kind) {
    case "circle":
      return Math.PI * shape.radius ** 2;
    case "square":
      return shape.sideLength ** 2;
    default:
      const _exhaustiveCheck: never = shape;
      return _exhaustiveCheck;
  }
}
Try

Adding a new member to the Shape union, will cause a TypeScript error:

ts
interface Triangle {
  kind: "triangle";
  sideLength: number;
}
 
type Shape = Circle | Square | Triangle;
 
function getArea(shape: Shape) {
  switch (shape.kind) {
    case "circle":
      return Math.PI * shape.radius ** 2;
    case "square":
      return shape.sideLength ** 2;
    default:
      const _exhaustiveCheck: never = shape;
Type 'Triangle' is not assignable to type 'never'.2322Type 'Triangle' is not assignable to type 'never'.
      return _exhaustiveCheck;
  }
}
Try

The TypeScript docs are an open source project. Help us improve these pages by sending a Pull Request ❤

Contributors to this page:
RCRyan Cavanaugh (52)
OTOrta Therox (15)
DRDaniel Rosenwasser (2)
AHAndrew Hunt (1)
SHSajad Hashemian (1)
14+

Last updated: Nov 19, 2022